Power Plant

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EE Hub โ€บ Power Plant โ€บ Thermal Steam
๐Ÿ”ฅ Thermal Power Plant: Overview
"In steam power plant, heat of combustion of fossil fuels is utilized by boilers to raise steam at high temperature and pressure."

Energy Conversion Chain:

$$ \text{Chemical (fuel)} \xrightarrow{\text{Boiler}} \text{Heat} \xrightarrow{\text{Steam}} \text{Pressure} \xrightarrow{\text{Turbine}} \text{Mechanical} \xrightarrow{\text{Gen}} \text{Electrical} $$

Why Thermal?

โ–ธ 61.1% of India's generation
โ–ธ Near load centre โ†’ low TL cost
โ–ธ Controllable output
โ–ธ Available 24ร—7

Fuels Used

โ–ธ Coal (most common)
โ–ธ Oil, Natural gas
โ–ธ Types: Anthracite, Bituminous, Lignite

Rankine Cycle (Ideal Steam Cycle):

1โ†’2 Isentropic expansion (turbine)
2โ†’3 Constant P condensation
3โ†’4 Isentropic pumping
4โ†’1 Constant P heat addition (boiler)
$$ \boxed{\eta_{Rankine} = \frac{W_{turbine} - W_{pump}}{Q_{boiler}} = \frac{(h_1-h_2)-(h_4-h_3)}{h_1-h_4}} $$

$\eta_{thermal,actual} \approx 30\text{-}40\%$

Overall & Heat Rate:

$$ \eta_{overall} = \eta_{boiler} \times \eta_{turbine} \times \eta_{generator} \times \eta_{mech} $$ $$ \text{Heat rate} = \frac{\text{Heat input (kJ)}}{\text{kWh generated}} \qquad \eta = \frac{3600}{\text{Heat rate}} $$
3,600
Ideal kJ/kWh
8,000โ€“12,000
Actual kJ/kWh

Major Components:

๐Ÿ”ฅ
Boiler
โš™๏ธ
Turbine
โ„๏ธ
Condenser
๐Ÿ’ง
Feed Pump
๐Ÿ—ผ
Cooling Tower
๐Ÿชจ
Coal Plant
๐ŸŒซ๏ธ
Ash Handling
โ™จ๏ธ
Superheater

๐Ÿญ Complete Thermal Plant Flow

Coal Boiler ๐Ÿ”ฅ Furnace Steam Superheater Turbine โš™๏ธ Spinning G โšก Grid Condenser Cooling Tower Pump Stack

๐Ÿ“Š Rankine Cycle Efficiency

RANKINE PROCESS

s (entropy) T 1โ†’2 Turbine 2โ†’3 Condenser 3โ†’4 Pump 4โ†’1 Boiler 1 2 3 4

ENERGY SANKEY FLOW

Input
Boiler loss
Turbine loss
Condenser
Gen loss
Output

๐Ÿงฎ Rankine Efficiency Calculator

๐Ÿญ Overall Thermal Efficiency

๐ŸŒก๏ธ Heat Rate Gauge

IDEAL
3,600
kJ/kWh
โ†’
ACTUAL
10,000
kJ/kWh
=
ฮท
36%
3600/10000
๐Ÿ“Š Hydro + Thermal Complete Summary

๐Ÿ’ง All Key Hydro Formulas

$P_{kW} = 9.81 \times 10^{-3} \cdot WQH\eta$
$P_{HP} = WQH\eta / 75$
$N_s = N\sqrt{P}/H^{5/4}$
$H_{net} = H_g - H_f$
$H_f = fLV^2/(2gD)$ (Darcy)
$H_f = 4f'LV^2/(2gD)$ (Fanning)
$f_{Darcy} = 4f_{Fanning}$

๐Ÿ”ฅ Thermal Formulas

$\eta_{Rankine} = \frac{(h_1-h_2)-(h_4-h_3)}{h_1-h_4}$
$\eta = 3600/\text{Heat rate}$
$\eta_{overall} = \prod \eta_i$
Heat rate: ideal 3600 kJ/kWh
Actual: 8000โ€“12000 kJ/kWh

Turbine Selection Guide:

H < 30 m

Kaplan

Ns = 300โ€“900

30 < H < 300 m

Francis

Ns = 50โ€“300

H > 300 m

Pelton

Ns = 10โ€“50

โšก Master Turbine Selector

โšก Complete Hydro Power Calculator

Module 2 โ€” Thermal (Steam) Power Plant
๐Ÿ”ฅ Module 2 ยท Energy Flow & System Overview
A Thermal Power Plant converts chemical energy in fossil fuels (coal, gas, oil) to electrical energy through a heatโ†’mechanicalโ†’electrical chain. The Rankine Cycle is the theoretical basis for steam plant operation.
Energy Conversion Chain
$$\text{Fuel (Chemical)} \xrightarrow{\text{Boiler}} \text{Steam (Thermal)} \xrightarrow{\text{Turbine}} \text{Shaft (Mech)} \xrightarrow{\text{Generator}} \text{Electricity}$$
Rankine Cycle Key Processes
$$1 \to 2:\;\text{Isentropic expansion in turbine}\quad W_T = h_1 - h_2$$
$$2 \to 3:\;\text{Constant-pressure heat rejection}\quad Q_{out} = h_2 - h_3$$
$$3 \to 4:\;\text{Isentropic compression in pump}\quad W_P = h_4 - h_3$$
$$4 \to 1:\;\text{Constant-pressure heat addition}\quad Q_{in} = h_1 - h_4$$
Cycle Efficiency
$$\eta_{Rankine} = \frac{W_T - W_P}{Q_{in}} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
Typical Efficiencies
ComponentSymbolTypical Range
Boilerฮทb85โ€“92%
Turbineฮทt80โ€“90%
Generatorฮทg95โ€“98%
Overall Plantฮทo33โ€“42%
๐Ÿ”ฅ Energy Flow Chain & Rankine Cycle
โ›๏ธ Fuel 100%
โ†’
๐Ÿ”ฅ Boiler ฮทb โ‰ˆ8โ€“15% loss
โ†’
๐Ÿ’จ Steam ~88%
โ†’
โš™๏ธ Turbine ฮทt โ‰ˆ10โ€“20% loss
โ†’
โšก Generator ฮทg โ‰ˆ2โ€“5% loss
โ†’
๐Ÿ”Œ Output ~36%
RANKINE CYCLE CALCULATOR
๐Ÿญ Module 2 ยท Single Line Diagram: Complete Plant
The thermal power plant converts fuel energy through four interconnected circuits: Coal & Ash, Air & Flue Gas, Feed Water & Steam, and Cooling Water. Each circuit forms a closed or open loop with dedicated components.
Key Process Equations
$$\text{Combustion:}\quad \text{C} + \text{O}_2 \to \text{CO}_2 + 393.5\;\text{kJ/mol}$$
$$\text{Steam Generation:}\quad Q_{boiler} = \dot{m}_s(h_1 - h_4)$$
$$\text{Turbine Work:}\quad W_T = \dot{m}_s(h_1 - h_2)$$
$$\text{Condenser Load:}\quad Q_c = \dot{m}_s(h_2 - h_3)$$
$$\text{Pump Work:}\quad W_P = \dot{m}_s \cdot v_f(P_4 - P_3)$$
Mass & Energy Balance
$$\dot{m}_{fuel} \times CV = \dot{m}_s(h_1 - h_4) / \eta_b$$
$$\text{Coal Rate} = \frac{3600 \times P_{MW}}{\eta_o \times CV} \;\text{tonnes/hr}$$

โšก Thermal Power Plant

ANIMATED PROCESS FLOW DIAGRAM
Coal / Ash
Steam Cycle
Flue Gases / Air
Cooling Water
Electricity
Coal Storage Coal Handling Plant Ash Storage Ash Handling Plant BOILER ๐Ÿ”ฅ HIGH TEMP Super Heater Valve TURBINE ALTERNATOR Feed Water Heater FEED PUMP CONDENSER Cooling Tower Water Treatment Plant Natural Water Source Economizer Air Preheater Hot Air Flue Gases Flue Gases Flue Gases Induced Draught Fan Forced Draught Fan Chim- ney Exhaust Steam

COAL โ†’ STEAM โ†’ TURBINE โ†’ ELECTRICITY  |  ANIMATED PROCESS FLOW

๐Ÿ”ง Module 2 ยท Components of Steam Power Plant
A modern steam power plant has 13+ major components working in concert. Each component has specific thermodynamic functions, design parameters, and efficiency targets.
Boiler Efficiency (Direct Method)
$$\eta_{boiler} = \frac{\dot{m}_s(h_1 - h_{fw})}{m_f \times CV} \times 100\%$$
Superheater & Economiser
$$Q_{SH} = \dot{m}_s(h_{sup} - h_{sat})$$
$$Q_{eco} = \dot{m}_s \cdot C_{pw}(T_{fw,out} - T_{fw,in})$$
Condenser Performance
$$\text{Vacuum Efficiency} = \frac{P_{barometric} - P_{condenser}}{P_{barometric}} \times 100\%$$
$$\text{Condenser Efficiency} = \frac{T_{sat} - T_{cw,out}}{T_{sat} - T_{cw,in}} \times 100\%$$
Draught Pressure (Natural)
$$h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right) \;\text{mm of water}$$
Boiler Types
FeatureFire-TubeWater-Tube
Gases flow inTubesOutside tubes
Water inShellTubes
Pressureโ‰ค 25 barUp to 200+ bar
CapacitySmall (โ‰ค 15 T/hr)Large (up to 2000 T/hr)
ExamplesLancashire, CochranBabcock-Wilcox, Benson
๐Ÿ”ง Plant Components Explorer
Fire-Tube: Hot gases flow inside tubes, water surrounds them in shell. Simple, low pressure (โ‰ค25 bar). E.g. Lancashire, Cochran, Locomotive boilers.
๐Ÿ”ฅ Boiler Converts water to steam using combustion heat. Types: fire-tube, water-tube. ฮท: 85โ€“92%
๐ŸŒก๏ธ Superheater Raises steam temp beyond saturation. Convective or radiant type. Improves ฮท & reduces moisture.
โ™ป๏ธ Economiser Pre-heats feed water using exhaust gas. Saves 5โ€“10% fuel. Placed after superheater in gas path.
๐ŸŒฌ๏ธ Air Pre-heater Heats combustion air using flue gas. Recuperative or regenerative (Ljungstrรถm). Improves combustion.
โš™๏ธ Turbine Converts steam kinetic energy to shaft work. Types: impulse (De Laval, Curtis) & reaction (Parsons). ฮท: 80โ€“90%
โšก Generator Converts mechanical to electrical energy. Synchronous type, 3000/3600 RPM. ฮท: 95โ€“98%
โ„๏ธ Condenser Condenses exhaust steam at low pressure. Surface or jet type. Creates vacuum for better turbine ฮท.
๐Ÿ’จ Cooling Tower Rejects heat from cooling water to atmosphere. Natural draught (hyperbolic) or mechanical draught.
โฌ†๏ธ BF Pump Boiler Feed Pump raises water pressure to boiler level. Centrifugal, multi-stage. Consumes 2โ€“3% of plant output.
๐Ÿงน ESP Electrostatic Precipitator removes 99%+ fly ash. Corona discharge charges particles for collection.
๐ŸŒซ๏ธ ID Fan Induced Draught fan pulls flue gas through boiler. Creates negative pressure in furnace.
๐ŸŒฌ๏ธ FD Fan Forced Draught fan pushes air into furnace. Creates positive pressure. Located before air pre-heater.
๐Ÿญ Chimney Discharges flue gas at height for dispersion. Provides natural draught. Height: 150โ€“275 m for modern plants.
๐Ÿ”„ Module 2 ยท Four Circuits in Detail
Every thermal power plant operates through four interconnected circuits. Understanding each circuit's components, flow path, and losses is essential for plant design and operation.
1. Coal & Ash Circuit
$$\text{Coal consumption} = \frac{P_{MW} \times 3600}{\eta_{overall} \times CV} \;\text{tonnes/hr}$$
$$\text{Ash produced} = \text{Coal} \times \text{Ash fraction} \;\text{(typically }30\text{โ€“}45\%\text{ for Indian coal)}$$
2. Air & Flue Gas Circuit
$$\text{Air required} = \frac{\text{kg of air}}{\text{kg of fuel}} \approx 15\text{โ€“}20\;\text{(with excess air)}$$
$$\text{Natural draught:}\quad h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right)$$
$$\text{Chimney height for draught:}\quad H = \frac{h_w}{353\left(\frac{1}{T_a} - \frac{1}{T_g}\right)}$$
3. Feed Water & Steam Circuit
$$\text{Steam rate} = \frac{3600}{W_{net}} \;\text{kg/kWh}$$
$$\text{Reheat improvement:}\quad \Delta\eta \approx 3\text{โ€“}5\%$$
4. Cooling Water Circuit
$$Q_{rejected} = \dot{m}_{cw} \times C_p \times \Delta T_{cw}$$
$$\text{CW flow rate} = \frac{Q_c}{C_p \times \Delta T_{cw}} \;\text{m}^3\text{/hr}$$
๐Ÿ”„ Circuit Calculators
COAL CONSUMPTION CALCULATOR
๐Ÿ“Š Module 2 ยท Thermal Plant Efficiency Analysis
Plant efficiency is the ratio of electrical output to fuel energy input. Three efficiency benchmarks: Carnot (theoretical max), Rankine (ideal cycle), and Actual (with losses). Modern plants achieve 36โ€“42% overall efficiency.
Carnot Efficiency (Theoretical Maximum)
$$\eta_{Carnot} = 1 - \frac{T_{sink}}{T_{source}} = 1 - \frac{T_L}{T_H}$$
Rankine Efficiency (Ideal Cycle)
$$\eta_{Rankine} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
Heat Rate & Heat Balance
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
$$\eta_{overall} = \eta_{boiler} \times \eta_{turbine} \times \eta_{generator} \times \eta_{aux}$$
Improvement Methods
Methodฮท ImprovementMechanism
Reheat+3โ€“5%Steam re-enters boiler between HP & LP stages
Regeneration+3โ€“5%Feed water heated by extracted steam
Supercritical+3โ€“4%Higher P & T โ†’ higher Carnot limit
Combined Cycle+15โ€“20%Gas turbine exhaust drives steam cycle
Energy Balance (per 100% fuel input)
Item% of Input
Electrical Output33โ€“42%
Condenser Loss38โ€“45%
Flue Gas Loss6โ€“10%
Boiler Radiation1โ€“2%
Unburnt Fuel1โ€“3%
Auxiliary Power5โ€“8%
๐Ÿ“Š Efficiency Analysis Dashboard
ENERGY BALANCE (SANKEY)
Fuel Input
100%
Elec Output
36%
Condenser
42%
Flue Gas
8%
Other Losses
14%
CARNOT vs RANKINE vs ACTUAL
HEAT RATE vs EFFICIENCY
๐Ÿ“‘ Module 2 ยท Complete Reference & Master Calculator
Comprehensive reference card combining all Module 2 formulas, component data, and a master thermal plant calculator for quick problem solving.
Master Formula Sheet
$$\eta_{Carnot} = 1 - \frac{T_L}{T_H}$$
$$\eta_{Rankine} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
$$\eta_{overall} = \eta_b \times \eta_t \times \eta_g \times \eta_{aux}$$
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
$$\text{Coal Rate} = \frac{P_{MW} \times 3600}{\eta_o \times CV} \;\text{tonnes/hr}$$
$$h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right) \;\text{mm of water}$$
$$\eta_{boiler} = \frac{\dot{m}_s(h_1 - h_{fw})}{m_f \times CV} \times 100\%$$
$$Q_{rejected} = \dot{m}_{cw} \times C_p \times \Delta T_{cw}$$
Quick Reference: Indian Thermal Plants
PlantCapacityTypeState
Vindhyachal4,760 MWCoalMadhya Pradesh
Mundra4,620 MWCoalGujarat
Talcher3,000 MWCoalOdisha
Sipat2,980 MWCoalChhattisgarh
Rihand3,000 MWCoalUttar Pradesh
๐Ÿ“‘ Master Thermal Plant Calculator
COMPLETE THERMAL PLANT ANALYSIS
โ€”
Overall ฮท
โ€”
Heat Rate
โ€”
Coal t/hr
โ€”
Carnot ฮท
Module 3 โ€” Coal Classification & Nuclear Power Plant
โ† Hydro Power All Topics Coal & Fuels โ†’
โ†‘