๐ฅ Thermal Power Plant: Overview
"In steam power plant, heat of combustion of fossil fuels is utilized by boilers to raise steam at high temperature and pressure."
Energy Conversion Chain:
$$ \text{Chemical (fuel)} \xrightarrow{\text{Boiler}} \text{Heat} \xrightarrow{\text{Steam}} \text{Pressure} \xrightarrow{\text{Turbine}} \text{Mechanical} \xrightarrow{\text{Gen}} \text{Electrical} $$
Why Thermal?
โธ 61.1% of India's generation
โธ Near load centre โ low TL cost
โธ Controllable output
โธ Available 24ร7
โธ Near load centre โ low TL cost
โธ Controllable output
โธ Available 24ร7
Fuels Used
โธ Coal (most common)
โธ Oil, Natural gas
โธ Types: Anthracite, Bituminous, Lignite
โธ Oil, Natural gas
โธ Types: Anthracite, Bituminous, Lignite
Rankine Cycle (Ideal Steam Cycle):
1โ2 Isentropic expansion (turbine)
2โ3 Constant P condensation
3โ4 Isentropic pumping
4โ1 Constant P heat addition (boiler)
$$ \boxed{\eta_{Rankine} = \frac{W_{turbine} - W_{pump}}{Q_{boiler}} = \frac{(h_1-h_2)-(h_4-h_3)}{h_1-h_4}} $$
$\eta_{thermal,actual} \approx 30\text{-}40\%$
Overall & Heat Rate:
$$ \eta_{overall} = \eta_{boiler} \times \eta_{turbine} \times \eta_{generator} \times \eta_{mech} $$
$$ \text{Heat rate} = \frac{\text{Heat input (kJ)}}{\text{kWh generated}} \qquad \eta = \frac{3600}{\text{Heat rate}} $$
3,600
Ideal kJ/kWh
8,000โ12,000
Actual kJ/kWh
Major Components:
๐ฅ
Boiler
โ๏ธ
Turbine
โ๏ธ
Condenser
๐ง
Feed Pump
๐ผ
Cooling Tower
๐ชจ
Coal Plant
๐ซ๏ธ
Ash Handling
โจ๏ธ
Superheater
๐ญ Complete Thermal Plant Flow
๐ Rankine Cycle Efficiency
RANKINE PROCESS
ENERGY SANKEY FLOW
Input
Boiler loss
Turbine loss
Condenser
Gen loss
Output
๐งฎ Rankine Efficiency Calculator
๐ญ Overall Thermal Efficiency
๐ก๏ธ Heat Rate Gauge
IDEAL
3,600
kJ/kWh
โ
ACTUAL
10,000
kJ/kWh
=
ฮท
36%
3600/10000
๐ Hydro + Thermal Complete Summary
๐ง All Key Hydro Formulas
$P_{kW} = 9.81 \times 10^{-3} \cdot WQH\eta$
$P_{HP} = WQH\eta / 75$
$N_s = N\sqrt{P}/H^{5/4}$
$H_{net} = H_g - H_f$
$H_f = fLV^2/(2gD)$ (Darcy)
$H_f = 4f'LV^2/(2gD)$ (Fanning)
$f_{Darcy} = 4f_{Fanning}$
$P_{HP} = WQH\eta / 75$
$N_s = N\sqrt{P}/H^{5/4}$
$H_{net} = H_g - H_f$
$H_f = fLV^2/(2gD)$ (Darcy)
$H_f = 4f'LV^2/(2gD)$ (Fanning)
$f_{Darcy} = 4f_{Fanning}$
๐ฅ Thermal Formulas
$\eta_{Rankine} = \frac{(h_1-h_2)-(h_4-h_3)}{h_1-h_4}$
$\eta = 3600/\text{Heat rate}$
$\eta_{overall} = \prod \eta_i$
Heat rate: ideal 3600 kJ/kWh
Actual: 8000โ12000 kJ/kWh
$\eta = 3600/\text{Heat rate}$
$\eta_{overall} = \prod \eta_i$
Heat rate: ideal 3600 kJ/kWh
Actual: 8000โ12000 kJ/kWh
Turbine Selection Guide:
H < 30 m
Kaplan
Ns = 300โ900
30 < H < 300 m
Francis
Ns = 50โ300
H > 300 m
Pelton
Ns = 10โ50
โก Master Turbine Selector
โก Complete Hydro Power Calculator
Module 2 โ Thermal (Steam) Power Plant
๐ฅ
Module 2 ยท Energy Flow & System Overview
A Thermal Power Plant converts chemical energy in fossil fuels (coal, gas, oil) to electrical energy through a heatโmechanicalโelectrical chain. The Rankine Cycle is the theoretical basis for steam plant operation.
Energy Conversion Chain
$$\text{Fuel (Chemical)} \xrightarrow{\text{Boiler}} \text{Steam (Thermal)} \xrightarrow{\text{Turbine}} \text{Shaft (Mech)} \xrightarrow{\text{Generator}} \text{Electricity}$$
Rankine Cycle Key Processes
$$1 \to 2:\;\text{Isentropic expansion in turbine}\quad W_T = h_1 - h_2$$
$$2 \to 3:\;\text{Constant-pressure heat rejection}\quad Q_{out} = h_2 - h_3$$
$$3 \to 4:\;\text{Isentropic compression in pump}\quad W_P = h_4 - h_3$$
$$4 \to 1:\;\text{Constant-pressure heat addition}\quad Q_{in} = h_1 - h_4$$
Cycle Efficiency
$$\eta_{Rankine} = \frac{W_T - W_P}{Q_{in}} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
Typical Efficiencies
| Component | Symbol | Typical Range |
|---|---|---|
| Boiler | ฮทb | 85โ92% |
| Turbine | ฮทt | 80โ90% |
| Generator | ฮทg | 95โ98% |
| Overall Plant | ฮทo | 33โ42% |
๐ฅ Energy Flow Chain & Rankine Cycle
Fuel
100%
โ
Boiler
ฮทb
โ8โ15% loss
โ
Steam
~88%
โ
Turbine
ฮทt
โ10โ20% loss
โ
Generator
ฮทg
โ2โ5% loss
โ
Output
~36%
RANKINE CYCLE CALCULATOR
๐ญ
Module 2 ยท Single Line Diagram: Complete Plant
The thermal power plant converts fuel energy through four interconnected circuits: Coal & Ash, Air & Flue Gas, Feed Water & Steam, and Cooling Water. Each circuit forms a closed or open loop with dedicated components.
Key Process Equations
$$\text{Combustion:}\quad \text{C} + \text{O}_2 \to \text{CO}_2 + 393.5\;\text{kJ/mol}$$
$$\text{Steam Generation:}\quad Q_{boiler} = \dot{m}_s(h_1 - h_4)$$
$$\text{Turbine Work:}\quad W_T = \dot{m}_s(h_1 - h_2)$$
$$\text{Condenser Load:}\quad Q_c = \dot{m}_s(h_2 - h_3)$$
$$\text{Pump Work:}\quad W_P = \dot{m}_s \cdot v_f(P_4 - P_3)$$
Mass & Energy Balance
$$\dot{m}_{fuel} \times CV = \dot{m}_s(h_1 - h_4) / \eta_b$$
$$\text{Coal Rate} = \frac{3600 \times P_{MW}}{\eta_o \times CV} \;\text{tonnes/hr}$$
๐ง
Module 2 ยท Components of Steam Power Plant
A modern steam power plant has 13+ major components working in concert. Each component has specific thermodynamic functions, design parameters, and efficiency targets.
Boiler Efficiency (Direct Method)
$$\eta_{boiler} = \frac{\dot{m}_s(h_1 - h_{fw})}{m_f \times CV} \times 100\%$$
Superheater & Economiser
$$Q_{SH} = \dot{m}_s(h_{sup} - h_{sat})$$
$$Q_{eco} = \dot{m}_s \cdot C_{pw}(T_{fw,out} - T_{fw,in})$$
Condenser Performance
$$\text{Vacuum Efficiency} = \frac{P_{barometric} - P_{condenser}}{P_{barometric}} \times 100\%$$
$$\text{Condenser Efficiency} = \frac{T_{sat} - T_{cw,out}}{T_{sat} - T_{cw,in}} \times 100\%$$
Draught Pressure (Natural)
$$h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right) \;\text{mm of water}$$
Boiler Types
| Feature | Fire-Tube | Water-Tube |
|---|---|---|
| Gases flow in | Tubes | Outside tubes |
| Water in | Shell | Tubes |
| Pressure | โค 25 bar | Up to 200+ bar |
| Capacity | Small (โค 15 T/hr) | Large (up to 2000 T/hr) |
| Examples | Lancashire, Cochran | Babcock-Wilcox, Benson |
๐ง Plant Components Explorer
Fire-Tube: Hot gases flow inside tubes, water surrounds them in shell. Simple, low pressure (โค25 bar). E.g. Lancashire, Cochran, Locomotive boilers.
Boiler
Converts water to steam using combustion heat. Types: fire-tube, water-tube. ฮท: 85โ92%
Superheater
Raises steam temp beyond saturation. Convective or radiant type. Improves ฮท & reduces moisture.
Economiser
Pre-heats feed water using exhaust gas. Saves 5โ10% fuel. Placed after superheater in gas path.
Air Pre-heater
Heats combustion air using flue gas. Recuperative or regenerative (Ljungstrรถm). Improves combustion.
Turbine
Converts steam kinetic energy to shaft work. Types: impulse (De Laval, Curtis) & reaction (Parsons). ฮท: 80โ90%
Generator
Converts mechanical to electrical energy. Synchronous type, 3000/3600 RPM. ฮท: 95โ98%
Condenser
Condenses exhaust steam at low pressure. Surface or jet type. Creates vacuum for better turbine ฮท.
Cooling Tower
Rejects heat from cooling water to atmosphere. Natural draught (hyperbolic) or mechanical draught.
BF Pump
Boiler Feed Pump raises water pressure to boiler level. Centrifugal, multi-stage. Consumes 2โ3% of plant output.
ESP
Electrostatic Precipitator removes 99%+ fly ash. Corona discharge charges particles for collection.
ID Fan
Induced Draught fan pulls flue gas through boiler. Creates negative pressure in furnace.
FD Fan
Forced Draught fan pushes air into furnace. Creates positive pressure. Located before air pre-heater.
Chimney
Discharges flue gas at height for dispersion. Provides natural draught. Height: 150โ275 m for modern plants.
๐
Module 2 ยท Four Circuits in Detail
Every thermal power plant operates through four interconnected circuits. Understanding each circuit's components, flow path, and losses is essential for plant design and operation.
1. Coal & Ash Circuit
$$\text{Coal consumption} = \frac{P_{MW} \times 3600}{\eta_{overall} \times CV} \;\text{tonnes/hr}$$
$$\text{Ash produced} = \text{Coal} \times \text{Ash fraction} \;\text{(typically }30\text{โ}45\%\text{ for Indian coal)}$$
2. Air & Flue Gas Circuit
$$\text{Air required} = \frac{\text{kg of air}}{\text{kg of fuel}} \approx 15\text{โ}20\;\text{(with excess air)}$$
$$\text{Natural draught:}\quad h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right)$$
$$\text{Chimney height for draught:}\quad H = \frac{h_w}{353\left(\frac{1}{T_a} - \frac{1}{T_g}\right)}$$
3. Feed Water & Steam Circuit
$$\text{Steam rate} = \frac{3600}{W_{net}} \;\text{kg/kWh}$$
$$\text{Reheat improvement:}\quad \Delta\eta \approx 3\text{โ}5\%$$
4. Cooling Water Circuit
$$Q_{rejected} = \dot{m}_{cw} \times C_p \times \Delta T_{cw}$$
$$\text{CW flow rate} = \frac{Q_c}{C_p \times \Delta T_{cw}} \;\text{m}^3\text{/hr}$$
๐ Circuit Calculators
COAL CONSUMPTION CALCULATOR
๐
Module 2 ยท Thermal Plant Efficiency Analysis
Plant efficiency is the ratio of electrical output to fuel energy input. Three efficiency benchmarks: Carnot (theoretical max), Rankine (ideal cycle), and Actual (with losses). Modern plants achieve 36โ42% overall efficiency.
Carnot Efficiency (Theoretical Maximum)
$$\eta_{Carnot} = 1 - \frac{T_{sink}}{T_{source}} = 1 - \frac{T_L}{T_H}$$
Rankine Efficiency (Ideal Cycle)
$$\eta_{Rankine} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
Heat Rate & Heat Balance
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
$$\eta_{overall} = \eta_{boiler} \times \eta_{turbine} \times \eta_{generator} \times \eta_{aux}$$
Improvement Methods
| Method | ฮท Improvement | Mechanism |
|---|---|---|
| Reheat | +3โ5% | Steam re-enters boiler between HP & LP stages |
| Regeneration | +3โ5% | Feed water heated by extracted steam |
| Supercritical | +3โ4% | Higher P & T โ higher Carnot limit |
| Combined Cycle | +15โ20% | Gas turbine exhaust drives steam cycle |
Energy Balance (per 100% fuel input)
| Item | % of Input |
|---|---|
| Electrical Output | 33โ42% |
| Condenser Loss | 38โ45% |
| Flue Gas Loss | 6โ10% |
| Boiler Radiation | 1โ2% |
| Unburnt Fuel | 1โ3% |
| Auxiliary Power | 5โ8% |
๐ Efficiency Analysis Dashboard
ENERGY BALANCE (SANKEY)
Fuel Input
100%
Elec Output
36%
Condenser
42%
Flue Gas
8%
Other Losses
14%
CARNOT vs RANKINE vs ACTUAL
HEAT RATE vs EFFICIENCY
๐
Module 2 ยท Complete Reference & Master Calculator
Comprehensive reference card combining all Module 2 formulas, component data, and a master thermal plant calculator for quick problem solving.
Master Formula Sheet
$$\eta_{Carnot} = 1 - \frac{T_L}{T_H}$$
$$\eta_{Rankine} = \frac{(h_1 - h_2) - (h_4 - h_3)}{h_1 - h_4}$$
$$\eta_{overall} = \eta_b \times \eta_t \times \eta_g \times \eta_{aux}$$
$$\text{Heat Rate} = \frac{3600}{\eta_{overall}} \;\text{kJ/kWh}$$
$$\text{Coal Rate} = \frac{P_{MW} \times 3600}{\eta_o \times CV} \;\text{tonnes/hr}$$
$$h_w = 353H\left(\frac{1}{T_a} - \frac{1}{T_g}\right) \;\text{mm of water}$$
$$\eta_{boiler} = \frac{\dot{m}_s(h_1 - h_{fw})}{m_f \times CV} \times 100\%$$
$$Q_{rejected} = \dot{m}_{cw} \times C_p \times \Delta T_{cw}$$
Quick Reference: Indian Thermal Plants
| Plant | Capacity | Type | State |
|---|---|---|---|
| Vindhyachal | 4,760 MW | Coal | Madhya Pradesh |
| Mundra | 4,620 MW | Coal | Gujarat |
| Talcher | 3,000 MW | Coal | Odisha |
| Sipat | 2,980 MW | Coal | Chhattisgarh |
| Rihand | 3,000 MW | Coal | Uttar Pradesh |
๐ Master Thermal Plant Calculator
COMPLETE THERMAL PLANT ANALYSIS
โ
Overall ฮท
โ
Heat Rate
โ
Coal t/hr
โ
Carnot ฮท
Module 3 โ Coal Classification & Nuclear Power Plant